• 코드

정답 코드 : 기존  N과 M (1)을 풀었던 코드에서 오름차순 일때만 추가할 수 있게 하였다.

 

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.util.StringTokenizer;

public class Main {
	private static int list[];
	private static boolean visit[];
	private static int n, m;
	private static StringBuilder sb;

	private static void dfs(int cnt) {
		if (cnt == m) {
			boolean check = true;
			for (int i = 1; i < m; i++) {
				if(list[i-1]>list[i])
					check = false;
			}
			if(check) {
				for (int i = 0; i < m; i++) {
					sb.append(list[i]).append(" ");
				}
				sb.append("\n");
			}
			return;
		}

		for (int i = 1; i <= n; i++) {
			if (visit[i])
				continue;
			visit[i] = true;
			list[cnt] = i;
			dfs(cnt + 1);
			visit[i] = false;
		}
	}

	public static void main(String[] args) throws IOException {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));

		StringTokenizer st = new StringTokenizer(br.readLine());
		n = Integer.parseInt(st.nextToken());
		m = Integer.parseInt(st.nextToken());

		list = new int[9];
		visit = new boolean[9];

		sb = new StringBuilder();

		dfs(0);

		bw.write(sb.toString());

		bw.close();
		br.close();
	}

}

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